The magnitude of the force (in N) acting on a body varies with time t (in μs) as shown. AB,BC and CD are straight line segments. The magnitude of the total impule of the force on the body from t=4μs to t=16μs is
A
5×10−3Ns
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5.8×10−3Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5.8×103Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5×103Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A5×10−3Ns We know that, Impulse=(Area of force-time graph under the specified interval) in the interval of (4μs to 16μs).
Hence the total area in the region of (4μs to 16μs) is =12(800+200)×2×10−6+12×800×10×10−6 =5×10−3Ns
The correct option is (a)