CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The magnitude of the force (in N) acting on a body varies with time t (in μs) as shown. AB,BC and CD are straight line segments. The magnitude of the total impule of the force on the body from t=4 μs to t=16 μs is

A
5×103 Ns
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5.8×103 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5.8×103 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5×103 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5×103 Ns
We know that,
Impulse=(Area of force-time graph under the specified interval) in the interval of (4 μs to 16 μs).
Hence the total area in the region of (4 μs to 16 μs) is
=12(800+200)×2×106+12×800×10×106
=5×103 Ns
The correct option is (a)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Summary and Misconceptions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon