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Quantum Numbers

The magnitude...

Question

The magnitude of the orbital angular momentum of an electron is given by $L = \frac{\sqrt{5} h}{π}$ . How many orbitals of this kind are possible for the subshell?

A

4

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B

11

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C

9

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D

5

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Solution

The correct option is C 9
Orbital angular momentum = $\sqrt{l (l + 1)} \frac{h}{2 π} w h e r e^{'} l^{'}$ is Azimuthal quantum number.
Given, $\sqrt{l (l + 1)} \frac{h}{2 π} = \sqrt{5} \frac{h}{π}$
$∴ l = 4$
So, number of possible orbitals = 2 $l$ + 1 = 9

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Quantum Numbers

Standard XII Chemistry

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