The magnitude of vector A-B- and C- are respectively 12- 5 and 13 units and A-B-C- then the angle between A- and B- is

C=√(A^2+B^2) The angle between A and B is π/2 ...

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Byju's Answer

Standard XIII

Physics

Vector Addition

The magnitude...

Question

The magnitude of vector $\to A, \to B$ and $\to C$ are respectively 12, 5 and 13 units and $\to A + \to B = \to C$ then the angle between $\to A$ and $\to B$ is

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$π$

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$\frac{π}{2}$

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$\frac{π}{4}$

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Solution

The correct option is C
$\frac{π}{2}$

$C = \sqrt{A^{2} + B^{2}}$
The angle between A and B is $\frac{π}{2}$

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The magnitude of vector →A,→B and →C are respectively 12, 5 and 13 units and →A+→B=→C then the angle between →A and →B is

The correct option is C π2 C=√A2+B2 The angle between A and B is π2

The magnitude of vector $\to A, \to B$ and $\to C$ are respectively 12, 5 and 13 units and $\to A + \to B = \to C$ then the angle between $\to A$ and $\to B$ is

The correct option is C
$\frac{π}{2}$

$C = \sqrt{A^{2} + B^{2}}$
The angle between A and B is $\frac{π}{2}$