The magnitude of vectors A- B- and C- are 6-8 and 10 units respectively where A-B-C- The angle between vectors A- and B- is in degreesA- 90B- 0C- 45D- 180

The correct option is A 90We know that the magnitude of resultant is given as : C = √(A^2+B^2+2ABcosθ) Placing A = 6, B = 8 and C = 10, we get θ = 90^0 ...

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Standard XII

Mathematics

Unit Vectors

The magnitude...

Question

The magnitude of vectors $\to A$ , $\to B$ and $\to C$ are 6, 8 and 10 units respectively where $\to A + \to B = \to C$ . The angle between vectors $\to A$ and $\to B$ is (in degrees)

0.0

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180

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Solution

The correct option is C 90
We know that the magnitude of resultant is given as :
$C = \sqrt{A^{2} + B^{2} + 2 A B c o s θ}$
Placing A = 6, B = 8 and C = 10, we get $θ = 90^{0}$

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