Question

The magnitude of work done (in Kcal) when 650 gm of zinc is reacted with an excess of HCl (aq) in an open vessel at 300 K is
[R $=$ 2 cal.mol${}^{-1},$ At. mass of Zn $=$ 65]

Answer 1

$Z{n}_{\left(s\right)}+2HC{l}_{\left(aq\right)}\to ZnC{l}_{2\left(aq\right)}+H_{2\left(g\right)}\to$

Work done, $W=-\Delta n\times RT$

$W=-\Delta n\times RT$

$W=-\frac{10\times 2\times 300}{1000}$

$W=-6Kcal$