The magnitudes of vectors A- B- and C- are 3-4 and 5 units respectively- If A-B-C- the angle between A- and B- isA- tan -17-5B- -2C- cos -10-6D- -4

The correct option is B π/2 C=√(A^2+B^2) =√(3^2+4^2)=5 ∴ Angle between A⃗ and B⃗ is π/2 ...

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Byju's Answer

Standard XII

Physics

Subtraction of a Vector

The magnitude...

Question

The magnitudes of vectors $\to A, \to B a n d \to C$ are 3, 4 and 5 units respectively. If $\to A + \to B = \to C$ , the angle between $\to A$ and $\to B$ is

$\frac{π}{2}$

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$c o s^{- 1} (0.6)$

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$t a n^{- 1} (\frac{7}{5})$

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$\frac{π}{4}$

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Solution

The correct option is A
$\frac{π}{2}$

$C = \sqrt{A^{2} + B^{2}} = \sqrt{3^{2} + 4^{2}} = 5$
$∴$ Angle between $\to A$ and $\to B$ is $\frac{π}{2}$

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The magnitudes of vectors $\to A, \to B a n d \to C$ are 3, 4 and 5 units respectively. If $\to A + \to B = \to C$ , the angle between $\to A$ and $\to B$ is

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The magnitudes of vectors →A,→Band→C are 3, 4 and 5 units respectively. If →A+→B=→C, the angle between →A and →B is

The correct option is A π2 C=√A2+B2=√32+42=5 ∴ Angle between →A and →B is π2

The magnitudes of vectors $\to A, \to B a n d \to C$ are 3, 4 and 5 units respectively. If $\to A + \to B = \to C$ , the angle between $\to A$ and $\to B$ is

The correct option is A
$\frac{π}{2}$

$C = \sqrt{A^{2} + B^{2}} = \sqrt{3^{2} + 4^{2}} = 5$
$∴$ Angle between $\to A$ and $\to B$ is $\frac{π}{2}$