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the maguitude...

Question

the maguitudes and directions of frictional forces at contact points

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Solution

$f_{1} = \frac{3 m_{1} F}{3 m_{1} + 8 m_{2}}$
$f_{2} = \frac{m_{1} F}{3 m_{1} + 8 m_{2}}$
Since. all quantities are positive, they are correctly shown in figures,
Note: Above calculllUons have been done at $t = 0$ when $ω = 0$

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