The correct option is B pπ−pπ back bonding
The strong 2pπ−2pπ back bonding between B and F atoms is responsible for the less acidic nature of boron fluoride. As we move down the group, the size of p orbitals increases and thus the strength of pπ−pπ back bonding decreases.
In BCl3 there will be 2pπ−3pπ back bonding.
In BBr3 there will be 2pπ−4pπ back bonding.
In BI3 there will be 2pπ−5pπ back bonding.
In the last three cases, the strength of pπ−pπ back bonding is less.
The acidic strength increases in the following order,
BF3<BCl3<BBr3<BI3