The main product obtained when a solution of sodium carbonate reacts with mercuric chloride is :

H g (O H)_{2}

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H g C O_{3} . H g O

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H g C O_{3}

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H g C O_{3} . H g (O H)_{2}

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Solution

The correct option is C $H g C O_{3} . H g O$
Mercuric chloride when heated with sodium carbonate solution, a yellow precipitate of mercuric oxide is formed.

$H g C l_{2} + N a_{2} C O_{3} \to H g O + 2 N a C l + C O_{2}$

Hence, option $B$ is correct.

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H g C O_{3}, C a C O_{3}, N a H C O_{3}, C H_{3} C H_{2} O H, A l_{2}, (S O_{4})_{2}

H C l

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