The main product of the reaction $C H_{3} C H_{2} B r$ and AgCN is:

$C H_{3} C H_{2} C N$

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$H_{3} C C H_{2} + N \equiv - C$

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$C H_{3} C H_{2} C H_{2} B r$

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$H_{2} C = C H_{2}$

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Solution

The correct option is B
$H_{3} C C H_{2} + N \equiv - C$

As covalent character of AgCN is higher, which do not get ionized hence nitrogen atom of Cyanide become donor,so alkyl group attacks from nitrogen side.

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Similar questions

The main product of the reaction $C H_{3} C H_{2} B r$ and AgCN is:

C H_{3} C H_{2} B r

C H_{3} C H_{2} C N

C H_{3} C H_{2} N C

C H_{3} C H_{2} C | B r H - C | B r H_{2} (i) K O H a l c . ⟶ (i i) N a N H_{2} i n l i q N H_{3}

{C H}_{3} - C l + A g C N \to P r o d u c t .

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