The main product of which of the following reactions gives tertiary sulphoamide with benzene sulphonyl chloride.

C_{6} H_{5} C l + 2 {N H}_{3} [{C u}_{2} O] - ------- \to 473 k 60 b a r

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{C H}_{3} {C H}_{2} {N O}_{2} L i A l H_{4} - --- \to

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{C H}_{3} {C H}_{2} N C L i A l H_{4} - --- \to

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{C H}_{3} C O {N H}_{2} {B r}_{2} / N a O H - ------ \to Δ

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Solution

The correct option is D ${C H}_{3} {C H}_{2} N C L i A l H_{4} - --- \to$
$C H_{3} - C H_{2} - N C L i A l H_{4} ⟶ C H_{3} - C H_{2} - N H - C H_{3}$
this is the main product of the following reactions gives tertiary sulphoamide with benzene sulphonyl chloride.

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