The main reason for larger number of oxidation state exhibited by the actinides than that corresponding lanthanide, is:
A
lesser energy difference between 5f and 6d orbitals than between 4f and 5d-orbitals
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
larger atomic size of actinides than the lanthanides
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
more energy differenc between 5f and 6d orbitals than between 4f and 5d-orbitals
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
greater reactive nature of the actinides than the lanthanides
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B lesser energy difference between 5f and 6d orbitals than between 4f and 5d-orbitals Unlike lanthanides, actinides show a variety of oxidation states from +3 to +6 due to the very small energy gap between 5f, 6d, and 7s subshells.
The principal oxidation states are +3 and +4. The +3 oxidation state is the most stable. The +4 oxidation state is the most stable in Th and Pu. +5 in Pa and Np and +6 is seen in U. In actinides, the distributions of oxidation states are uneven.