The main scale reading is 1 cm, the Vernier coincidence is 5, and the negative zero error is 0.02 cm. Calculate the correct reading.

1.03 cm

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1.05 cm

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1 cm

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1.07 cm

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Solution

The correct option is D 1.07 cm

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Similar questions

The main scale reading is 8 cm and vernier coincidence is 4 and negative zero error is 0.02 cm. Then calculate the correct reading:
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the least count of a vernier calliper is 0.01 cm and it has an error of +0.07 cm . While measuring the radius of a sphere , the main scale reading is 2.90cm and the 5th vernier scale div. coincides with main scale . Calculate the correct radius.

Q. The least count of a vernier callipers is 0.01 cm. It has an error of +0.02 cm while measuring the radius of a cylinder. The main scale reading is 3.60 cm and the 8th vernier scale division coincides with main scale, then what will be the correct radius of the cylinder?

Q. Consider the following data for a vernier calliper:
10 main scale division = 1 cm.
10 vernier division matches with 9 Main scale division.

While measuring the zero error of the vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with

6^{t h}

vernier division coinciding with main scale divisions.

The actual reading for length measurement is 4.3 cm with 2nd vernier division coinciding with main scale graduation.

Estimate the length.

6^{t h}

vernier division coinciding with main scale divisions.

The actual reading for length measurement is 4.3 cm with 2nd vernier division coinciding with main scale graduation.

Estimate the length.

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The main scale reading is 1 cm, the Vernier coincidence is 5, and the negative zero error is 0.02 cm. Calculate the correct reading. ​

The correct option is D 1.07 cm

The main scale reading is 1 cm, the Vernier coincidence is 5, and the negative zero error is 0.02 cm. Calculate the correct reading.