The main scale reading is 8 cm and vernier coincidence is 4 and negative zero error is 0.02 cm. Then calculate the correct reading:
[2marks]

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Solution

For a vernier calliper:
Actual scale reading = main scale reading + Vernier scale reading − (zero error found).
[1 Mark]

Correct reading = 8 cm + (4 × 0.01 cm) - (-0.02 cm)
= 8 cm + (4 × 0.01 cm) + (0.02 cm)
= 8+0.04+0.02
= 8.06 cm.
[1 Mark]

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6^{t h}

vernier division coinciding with main scale divisions.

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6^{t h}

vernier division coinciding with main scale divisions.

The actual reading for length measurement is 4.3 cm with 2nd vernier division coinciding with main scale graduation.

Estimate the length.

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The main scale reading is 8 cm and vernier coincidence is 4 and negative zero error is 0.02 cm. Then calculate the correct reading: [2marks]

For a vernier calliper: Actual scale reading = main scale reading + Vernier scale reading − (zero error found). [1 Mark] Correct reading = 8 cm + (4 × 0.01 cm) - (-0.02 cm) = 8 cm + (4 × 0.01 cm) + (0.02 cm) = 8+0.04+0.02 = 8.06 cm. [1 Mark]

The main scale reading is 8 cm and vernier coincidence is 4 and negative zero error is 0.02 cm. Then calculate the correct reading:
[2marks]

For a vernier calliper:
Actual scale reading = main scale reading + Vernier scale reading − (zero error found).
[1 Mark]

Correct reading = 8 cm + (4 × 0.01 cm) - (-0.02 cm)
= 8 cm + (4 × 0.01 cm) + (0.02 cm)
= 8+0.04+0.02
= 8.06 cm.
[1 Mark]