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Question
The major product obtained from E2 – elimination of 3-Bromo-2-fluoropentane is:
The major product obtained from E2 – elimination of 3-Bromo-2-fluoropentane is:
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Solution
The correct option is A
the correct answer is :(a)
The explanation for the correct options:
(a)
- Explanation: There may be a minor amount of 2-methyl-3-bromopentane, but 3-Bromo-3-methyl pentane is by far the more prevalent result. The H+ from HBr will combine with the alkene's C-2 and produce a 3° carbocation at C-3, in accordance with Markovnikov's rule.
- We observed the following reaction between tert-butyl bromide and cyanide at the beginning of this lesson. This is definitely not a substitution reaction.
- We are aware that an SN2 reaction is not anticipated for t-butyl bromide. Additionally, the ethanol solvent lacks enough polarity to support an SN1 reaction.
Diagram:
The explanation for the incorrect options:
(b)
- Explanation: Alkyl halides react with alcoholic KOH, favoring an elimination reaction, and this produces the main product. When compared to cis-isomers, trans-2-pentene is more symmetrical. Trans-2-pentene is the main product so generated.
- The other reactant, cyanide anion, is an effective nucleophile and a respectable base because it is about ten times less potent than bicarbonate.
Diagram:
(c)
- Explanation: Alkyl halides react with alcoholic KOH, favoring an elimination reaction, and this produces the main product. When compared to cis-isomers, trans-2-pentene is more symmetrical.
- Trans-2-pentene is the main product so generated. (Br)Methanethiolate has a 100-fold stronger nucleophilicity than methoxide in the methanol solvent employed in this experiment. In contrast, methoxide is approximately 106 times more basic than methanethiol. Because of this, we can clearly distinguish between nucleophilicity (bonding to an electrophilic carbon) and basicity in the reaction products (bonding to a proton).
Diagram:
(d)
- Explanation: The main product created when nitrobenzene is treated with bromine in the presence of ferric bromine is m-Bromo-nitrobenzene. Obtaining the "m-" isomer is related to the following statement.
- Because of this, we can clearly distinguish between nucleophilicity (bonding to an electrophilic carbon) and basicity in the reaction products (bonding to a proton).
Diagram:
the final answer is :(a)
the correct answer is :(a)
The explanation for the correct options:
(a)
- Explanation: There may be a minor amount of 2-methyl-3-bromopentane, but 3-Bromo-3-methyl pentane is by far the more prevalent result. The H+ from HBr will combine with the alkene's C-2 and produce a 3° carbocation at C-3, in accordance with Markovnikov's rule.
- We observed the following reaction between tert-butyl bromide and cyanide at the beginning of this lesson. This is definitely not a substitution reaction.
- We are aware that an SN2 reaction is not anticipated for t-butyl bromide. Additionally, the ethanol solvent lacks enough polarity to support an SN1 reaction.
Diagram:
The explanation for the incorrect options:
(b)
- Explanation: Alkyl halides react with alcoholic KOH, favoring an elimination reaction, and this produces the main product. When compared to cis-isomers, trans-2-pentene is more symmetrical. Trans-2-pentene is the main product so generated.
- The other reactant, cyanide anion, is an effective nucleophile and a respectable base because it is about ten times less potent than bicarbonate.
Diagram:
(c)
- Explanation: Alkyl halides react with alcoholic KOH, favoring an elimination reaction, and this produces the main product. When compared to cis-isomers, trans-2-pentene is more symmetrical.
- Trans-2-pentene is the main product so generated. (Br)Methanethiolate has a 100-fold stronger nucleophilicity than methoxide in the methanol solvent employed in this experiment. In contrast, methoxide is approximately 106 times more basic than methanethiol. Because of this, we can clearly distinguish between nucleophilicity (bonding to an electrophilic carbon) and basicity in the reaction products (bonding to a proton).
Diagram:
(d)
- Explanation: The main product created when nitrobenzene is treated with bromine in the presence of ferric bromine is m-Bromo-nitrobenzene. Obtaining the "m-" isomer is related to the following statement.
- Because of this, we can clearly distinguish between nucleophilicity (bonding to an electrophilic carbon) and basicity in the reaction products (bonding to a proton).
Diagram:
the final answer is :(a)
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