The major product obtained in the following reaction is :

C_{6} H_{5} C H = C H C_{6} H_{5}

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(+) C_{6} H_{5} C H (O^{t} B u) C H_{2} C_{6} H_{5}

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(-) C_{6} H_{5} C H (O^{t} B u) C H_{2} C_{6} H_{5}

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(\pm) C_{6} H_{5} C H (O^{t} B u) C H_{2} C_{6} H_{5}

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Solution

The correct option is B $C_{6} H_{5} C H = C H C_{6} H_{5}$
Alkene is the product as bulky hindered base and secondary alkyl bromide favors elimination over substitution.
Hence, the option (A) is the correct answer.

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