The major product of the following reaction is:
$C H_{3} C H = C H C O_{2} C H_{3} L i A l H_{4} - --- \to$

C H_{3} C H = C H C H_{2} O H

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C H_{3} C H_{2} C H_{2} C H_{2} O H

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C H_{3} C H_{2} C H_{2} C O_{2} C H_{3}

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C H_{3} C H_{2} C H_{2} C H O

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Solution

The correct option is A $C H_{3} C H = C H C H_{2} O H$
The reaction of an ester with $L i A l H_{4}$ produces two alcohols, one corresponding to the acyl portion of the ester and one corresponding to the alkyl portion.

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The major product of the following reaction is

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