The manifestation of band structure in solids is due to

Heisenberg's uncertainty principle

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Pauli's exclusion principle

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Bohr's correspondence principle

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Boltzmann's law

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Pauli's exclusion principle
The Pauli exclusion principle states that no two electrons may occupy the same quantum state in an atom simultaneously. In other words, no two electrons in the same atom can have the same four quantum numbers (principal quantum number, $n$ , the azimuthal quantum number, the magnetic quantum number, $m_{l}$ and magnetic spin $m_{s}$ ).
This makes the electrons to occupy a space which effectively form a continuous band structure or energy levels.

Suggest Corrections

Similar questions

If carbon atom has electronic configuration 1 $s^{6}$ , it would have energy lower than that of the normal ground state configuration 1 $s^{2}$ 2 $s^{2}$ 2 $p^{2}$ . Yet 1 $s^{6}$ is not observed because it violates

Nitrogen has the electronic configuration $1 s^{2}, 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$ and not $1 s^{2}, 2 s^{2} 2 p_{x}^{2} 2 p_{y}^{1} 2 p_{z}^{0}$ which is determined by

Q. If the nitrogen atom had an electronic configuration of

1 s^{7}

it would have lower energy than that of the normal ground state configuration

1 s^{2}, 2 s^{2}, 2 p^{3}

because the electrons would be closer to the nucleus.

1 s^{7}

is not observed because it violates:

Q. The Pauli exclusion principle applies to the following option:

The Pauli exclusion principle states that:

Join BYJU'S Learning Program