The map distance between genes A and B is 3 units, between B and C 10 units and between C and A 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be
A
A, B, C
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B
A, C, B
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C
B, C, A
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D
B, A, C
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Solution
The correct option is D B, A, C Distance between A and B is 3 units. Between B and C is 10 units. Between C and A is 7 units. So it can be marked as : B A C |------------|-------------------------| 3 Units 7 units