The map distances between genes A and B is 3 units, between B anc C is 10 units and between C and A is 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be:

A, B, C

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A, C, B

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B, C, A

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B, A, C

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Solution

The correct option is D
B, A, C

The gene map constructed on the above data is

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Similar questions

The map distance between genes A and B is 3 units, between B and C 10 units and between C and A 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be

The map distances between genes A and B is 3 units, between B anc C is 10 units and between C and A is 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be:

Q. If map distance between genes P and Q is 4 units, between P and R is 11 units, and between Q and R is 7 units, the order of genes on the linkage map can be traced as follows.

Q. What is the distance between the genes A and B?
(a) 20 map unit
(b) 10 map unit

Q. What should be the order of genes (A, B and C) in a chromosome when the map distance between genes are as follows:
i. A and B = 3 units
ii. B and C = 10 units
iii. C and A = 7 units

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The map distances between genes A and B is 3 units, between B anc C is 10 units and between C and A is 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be:

The correct option is D B, A, C The gene map constructed on the above data is

The correct option is D
B, A, C

The gene map constructed on the above data is