Mean of Ungrouped Frequency Distribution by Simple Method
The marks obt...
Question
The marks obtained by 40 students in a class are presented in the form of a table. Find the mean marks using direct method. Marks obtainedNumber of students0−10310−20420−301330−401540−505
A
28.75
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B
25.25
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C
26.44
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D
29.91
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Solution
The correct option is A 28.75 Class mark for first class interval =Upper class limit+Lower class limit2=0+102=5
Similarly the class mark for each class interval can be found. Look at the table. Class intervalNumber of students(fi)Class mark(xi)fixi0−10351510−204156020−30132532530−40153552540−50545225Total∑fi=40∑fixi=1150 Mean=∑fixi∑fi=115040=28.75