The marks obtained out of 50, by 102 students in a Physics test are given in the frequency table below:
Marks (x) : 15 20 22 24 25 30 33 38 45
Frequency (f) : 5 8 11 20 23 18 13 3 1
Find the average number of marks.

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Solution

$\sum x f = 2660$ , $\sum f = 102$
Average or mean $= \frac{\sum x f}{\sum f} = \frac{2660}{102} = 26.07$ .

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Similar questions

Q. The marks obtained out of

50

, by

102

students in a Physics test are given in the frequency table below:

Marks ( $x$ )	$15$	$20$	$22$	$24$	$25$	$30$	$33$	$28$	$45$
Frequency ( $f$ )	$5$	$8$	$11$	$20$	$23$	$18$	$13$	$3$	$1$

Find the average mark.

Q. The marks obtained out of 50, by 102 students in a Physics test are given in the frequency table below:

Marks (x):	15	20	22	24	25	30	33	38	45
Frequency (f):	5	8	11	20	23	18	13	3	1

Find the average number of marks.

The marks obtained out of 50, by 102 students in a Physics test are given in the frequency table below:
Marks (x) : 15 20 22 24 15 30 33 38 45
Frequency (f) : 5 8 11 20 23 18 13 3 1
Find the average number of marks.

Q. Given below are the marks obtained by

30

students in an examination:

$08$	$17$	$33$	$41$	$47$	$23$	$20$	$34$
$09$	$18$	$42$	$14$	$30$	$19$	$29$	$11$
$36$	$48$	$40$	$24$	$22$	$02$	$16$	$21$
$15$	$32$	$47$	$44$	$33$	$01$

Taking class intervals

1 - 10, 11 - 20 . . . . . . . . . . . . .41 - 50;

make a frequency table for the above distribution.

Q. The marks obtained by

36

students in a test in statistics (out of

50

) are as below.

3511535452331402113152047484234434533371113271812373938161318

5414743

Construct a frequency distribution table with equal class intervals, one of them being

10 - 20

(

20

is not included)

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The marks obtained out of 50, by 102 students in a Physics test are given in the frequency table below:Marks (x) : 15 20 22 24 25 30 33 38 45Frequency (f) : 5 8 11 20 23 18 13 3 1Find the average number of marks.

∑xf=2660, ∑f=102Average or mean =∑xf∑f=2660102=26.07.

The marks obtained out of 50, by 102 students in a Physics test are given in the frequency table below:
Marks (x) : 15 20 22 24 25 30 33 38 45
Frequency (f) : 5 8 11 20 23 18 13 3 1
Find the average number of marks.

$\sum x f = 2660$ , $\sum f = 102$
Average or mean $= \frac{\sum x f}{\sum f} = \frac{2660}{102} = 26.07$ .