Question

The mass defect in a nucleus is $3.5\text{amu}$. Then the binding energy of the nucleus is

• A. $3.258\text{MeV}$
• B. $32.58\text{MeV}$
• C. $325.8\text{MeV}$
• D. $3260.25\text{MeV}$

Answer 1

The correct option is D $3260.25\text{MeV}$

Given:
Mass defect $\Delta m=3.5\text{amu}$

$B.E=\Delta m\times c^2$

$\Rightarrow B.E=3.5\text{amu}\times c^2$

We know that,

$1\text{amu}\times c^2=931.5\text{MeV}$

$\Rightarrow B.E=3.5\times 931.5\text{MeV}$

$\Rightarrow \begin{array}{c}BE=3260.25\text{MeV}\end{array}$

Hence, option $\left(D\right)$ is correct.