The mass number of an element in a radioactive series is 223. Which radioactive series is this ?

The

4 n + 2

series

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The

4 n

series

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The

4 n + 1

series

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The

4 n + 3

series

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Solution

The correct option is D The $4 n + 3$ series
mass is 223
$4 n + 3 = 223 4 n = 220 n = \frac{220}{4} = 55 \to I n t e g e r$
So, 4n+3 series

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_{95} A m^{241} a n d_{90} T h^{234}

(4 n + 2)

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