The mass of $11.2 l i t r e s$ of a certain gas at s.t.p. is $24 g$ . Find the gram molecular mass of the gas.

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Solution

The mass of $11.2 l i t r e s$ of a certain gas at s.t.p. is $24 g$ . The gram molecular mass of the gas is $24 g \times \frac{22.4 L / m o l}{11.2 L} = 48 g / m o l$
Note: At s.t.p., 1 mole of any gas occupies a volume of 22.4 L.

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The mass of 11.2 litres of a certain gas at s.t.p. is 24 g. Find the gram molecular mass of the gas.

The mass of 11.2 litres of a certain gas at s.t.p. is 24 g. The gram molecular mass of the gas is 24g×22.4L/mol11.2L=48g/molNote: At s.t.p., 1 mole of any gas occupies a volume of 22.4 L.

The mass of $11.2 l i t r e s$ of a certain gas at s.t.p. is $24 g$ . Find the gram molecular mass of the gas.

The mass of $11.2 l i t r e s$ of a certain gas at s.t.p. is $24 g$ . The gram molecular mass of the gas is $24 g \times \frac{22.4 L / m o l}{11.2 L} = 48 g / m o l$
Note: At s.t.p., 1 mole of any gas occupies a volume of 22.4 L.