Question

The mass of $112$ $c{m}^3$ of methane at STP is:

• A. 0.16 g
• B. 0.08 g
• C. 0.8 g
• D. 16 g

Answer 1

The correct option is B 0.08 g

1 mole of a gas occupies 22.4 L of a gas at STP.

Since, the molecular weight of methane is 16 g,

Therefore, at STP, $22.4$ L corresponds to $16$ g.

$112$ $c{m}^3$ or $0.112$ L will correspond to $\frac{16}{22.4}\times 0.112=0.08g$.

Hence, option B is correct.