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Multi-Electron Configurations and Orbital Diagrams

The mass of ...

Question

The mass of $_{2} H e^{4}$ nnucleus is $0.03$ amu less than the sum of the masses of $2$ protons and $2$ neutrons. What is the binding energy per nucleon?

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Solution

Here, $△ m = 0.03 u$ (given)
So, $E = △ m c^{2} = 0.03 \times 931.5 = 27.945 M e V$

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