Question

The mass of $350{cm}^3$ of a diatomic gas at 273 K at 2 atmospheres pressure is one gram. Calculate the mass of one atom of the gas.

• A. $5.3\times {10}^{-23}g$
• B. $2.65\times {10}^{-23}g$
• C. $12.02\times {10}^{23}g$
• D. None of these

Answer 1

The correct option is A $5.3\times {10}^{-23}g$

$n=\frac{PV}{RT}$

$=\frac{2\times 0.35}{0.082\times 273}$

$\approx =0.031mol$

$0.031$ mol weight $1g$

$0.031\times 6022\times {10}^{23}atoms$= $1g$

$=\frac{1}{0.031\times 6.022}\times {10}^{-23}$

$=5.3\times {10}^{-23}g$