The mass of 5.6 litres of a certain gas at S.T.P. is 11 g. What is the relative molecular mass or molar mass of the gas?

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Solution

1 mole of a gas at S.T.P. occupies 22.4 L.
Also, 1 mole of a gas = Molecular mass of a gas.
$∴$ 22.4 L of a gas weighs = Molecular weight of the gas.
$\Rightarrow$ 1 L of a gas would weigh = $\frac{M o l e c u l a r w e i g h t o f t h e g a s .}{22.4 L}$
and 5.6 litres of a gas =. $\frac{M o l e c u l a r w e i g h t o f t h e g a s}{22.4} \times 5.6$
$\Rightarrow$ 11 g of a gas = $\frac{M o l e c u l a r w e i g h t o f t h e g a s}{22.4} \times 5.6$
$\Rightarrow$ Molecular weight of the gas = $\frac{11 \times 22.4}{5.6}$
Molecular weight of the gas = 44g

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