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Question

The mass of 70% H2SO4 required for neutralisation of 1 mole of NaOH is:

A
49 g
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B
98 g
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C
70 g
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D
34.3 g
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Solution

The correct option is C 70 g
H2SO4+2NaOHNa2SO4+2H2O
for neutralizing 1 mole NaOH,12 mole (49 g)H2SO4 is required.

Since, 70 g H2SO4 is in 100 gm of solution i.e. 70% H2SO4, it follows that:

49 g H2SO4 will be found in =10070×49=70 g solution.

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