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Question

The mass of 70% H2SO4 required for the neutralization of 1 mole of NaOH is :

A
70 g
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B
35 g
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C
30 g
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D
95 g
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Solution

The correct option is C 70 g
NaOH+H2SO4Na2SO4+2H2O
2 mol 1 mol
1 mol 0.5 mol =49 g H2SO4 (pure)
Thus, 70% H2SO4 required =49×10070=70 g

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