The mass of a bucket full of water is 15kg.It is being pulled up from a 15m deep well.Due to a hole in the bucket 6kg water flows out of the bucket.The work done in drawing the bucket out of the well will be(g=10m/s2)

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Q. The mass of a bucket full of water is

15 k g

. It is being pulled up from a

15 m

deep well. Due to a hole in the bucket

6 k g

water flows out of the bucket. The work done in drawing the bucket out of the well will be (

g = 10 m / s^{2}

Q. The mass of bucket full of water is 15 kg . It is being pulled up from a 15 m deep well. Due to a hole in the bucket 6 kg water flows out of the bucket at a uniform rate. The work done in drawing the bucket out of the well will be

(g = 10 m / s^{2}) -

Q. The mass of a bucket containing water is

M_{0}

. The bucket is pulled steadily up from a well of depth d. Due to a hole in the bucket the water is pouring out at a uniform rate and as a result the mass of the bucket with water at the top of the well reduces to M. Then the amount of work done in pulling up the bucket is?

Q. A man is drawing water from a well of depth 10 m using a bucket with hole in it, such that only half of the water remains when bucket arrives at top of the well.
When bucket is full of water, its mass is 40 kg and pulling rate of bucket is constant. The work done by man in kilo joules to pull bucket up is ( g = 10 m/

s^{2}

) [ Neglect weight of the bucket.]

The mass of a bucket containing water is 10 kg. What is the work done in pulling up the bucket from a well of depth 10 m if water is pouring out at a uniform rate from a hole in it and there is loss of 2kg of water from it while it reaches the top $(g = 10 m / s e c^{2})$

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