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Standard XII

Physics

Ideal Gas Equation

The mass of a...

Question

The mass of a gas molecules is 4x10 $^{- 30}$ kg. If 10 $^{23}$ molecules strike per second at 4m $^{2}$ area with a velocity 10 $^{7}$ m/s, then the pressure exerted on the surface will be

1 Pascal

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3 Pascal

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2 Pascal

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4 Pascal

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Solution

The correct option is B 2 Pascal
Change in momentum per molecule= $m v - m (- v) = 2 m v$
Force exerted= $2 m v n$
where n is number of molecules that strike per second.
$P r e s s u r e = F o r c e / A r e a = \frac{2 m n v}{A} = 2 P a$

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The mass of a gas molecules is 4x10−30kg. If 1023 molecules strike per second at 4m2 area with a velocity 107m/s, then the pressure exerted on the surface will be

The correct option is B 2 PascalChange in momentum per molecule=mv−m(−v)=2mvForce exerted=2mvnwhere n is number of molecules that strike per second.Pressure=Force/Area=2mnvA=2Pa

The mass of a gas molecules is 4x10 $^{- 30}$ kg. If 10 $^{23}$ molecules strike per second at 4m $^{2}$ area with a velocity 10 $^{7}$ m/s, then the pressure exerted on the surface will be

The correct option is B 2 Pascal
Change in momentum per molecule= $m v - m (- v) = 2 m v$
Force exerted= $2 m v n$
where n is number of molecules that strike per second.
$P r e s s u r e = F o r c e / A r e a = \frac{2 m n v}{A} = 2 P a$