The mass of a molecule of water is

3 \times 10^{- 26} k g

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3 \times 10^{- 25} k g

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1.5 \times 10^{- 26} k g

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2.5 \times 10^{- 26} k g

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Solution

The correct option is A $3 \times 10^{- 26} k g$
$6 .023 \times 10^{23}$ molecules have mass = $18$ g

$1$ molecule has mass =

$\frac{18}{6.023 \times 10^{23}}$ = $2.989 \times 10^{- 23} g$ = $2.989 \times 10^{- 26} k g$

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(m) = 2.76 \times 10^{- 26} k g

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