The mass of a planet is half that of the earth and the radius of the planet is one fourth that of earth. If we plan to send an artificial satellite from the planet, the escape velocity will be $($ $V_{e} = 11$ kms $^{- 1}$ $)$ :

11

kms

^{- 1}

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5.5

kms

^{- 1}

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15.55

kms

^{- 1}

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7.78

kms

^{- 1}

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Solution

The correct option is D $15.55$ kms $^{- 1}$
Escape speed is $v_{e} = \sqrt{\frac{2 G M}{R}} = 11$ km/s on Earth's surface.
Given the mass is half and radius is one fourth that of Earth's. So, $v_{e}^{^{'}} = \sqrt{\frac{2 G \times M / 2}{R / 4}} = \sqrt{2} \times \sqrt{\frac{2 G M}{R}} = 1.414 \times 11 = 15.554$ km/s

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The mass of a planet is half that of the earth and the radius of the planet is one fourth that of earth. If we plan to send an artificial satellite from the planet, the escape velocity will be( Ve=11 kms−1 ):

The correct option is D 15.55 kms−1Escape speed is ve=√2GMR=11 km/s on Earth's surface.Given the mass is half and radius is one fourth that of Earth's. So,v′e=√2G×M/2R/4=√2×√2GMR=1.414×11=15.554 km/s

The mass of a planet is half that of the earth and the radius of the planet is one fourth that of earth. If we plan to send an artificial satellite from the planet, the escape velocity will be $($ $V_{e} = 11$ kms $^{- 1}$ $)$ :