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Question

The mass of a specimen of a ferromagnetic material is 0.5 kg and its density is 8000 kg/m3. What is the energy equivalent area of hysteresis loop of alternating magnetizing field of frequency 100 Hz, if the hysteresis loss per second is 240×10−3 J/s?

A
3.84 J/m3
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B
1.92 J/m3
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C
38.4 J/m3
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D
19.2 J/m3
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Solution

The correct option is C 38.4 J/m3Given, m=0.5 kg; ρ=8000 kg/m3; n=100 Hz Hysteresis loss per second, E=240×10−3 J/s Area of hysteresis loop gives the loss of energy per unit volume of material in one cycle of magnetization and demagnetization. So, total loss per unit time is, E= Area × volume× Frequency Substituting the values, we get, 240×10−3=Area×0.58000×100 ∴Area=38.4 J/m3 Hence, option (C) is the correct answer.

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