The mass of an atom of C is

$1 g$

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$1.99 \times 10^{- 23} g$

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$\frac{1}{12}$

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$1.99 \times 10^{- 20} g$

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Solution

The correct option is B
$1.99 \times 10^{- 23} g$

1 mole of carbon = $6.022 \times 10^{23}$ C atoms

$6.022 \times 10^{23}$ C atoms = 12 g (gram atomic mass of carbon)

1 C atom = $\frac{12}{6.022 \times 10^{23}} = 1.99 \times 10^{- 23} g$

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