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Question

The mass of an electron is 9.1×1028 g and the uncertainty in velocity is equal to 2×103cm/sec. The uncertainty in the position of an electron is:


[h=6.62×1027 erg sec]

A
2.9×102 cm
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B
2.9×102 cm
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C
2.9×1012 cm
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D
None of these
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Solution

The correct option is A 2.9×102 cm
Using the formula: Δx×Δp=h4π.

Now, Δp=mΔv=9.1×1028gm×2×103cm/sec=1.82×1030gmcm/sec=1.82×1035 kgm/sec

Therefore, Δx=h4πΔp=2.9m=2.9×102cm.

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