The mass of an electron is $9.11 \times 10^{- 31}$ kg, that of a proton is $1.67 \times 10^{- 27}$ kg, Find the ratio $F_{e} / F_{g}$ of the electric force and the gravitational force exerted by the proton on the electron.

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Solution

$F_{e} = \frac{1}{4 π ϵ} \frac{q_{e}^{2}}{r^{2}}$
$F_{g} = G \frac{m_{e} M_{p}}{r^{2}}$ ( $G = 6.67 \times 10^{- 11} m^{3} k g^{- 1} s^{- 2})$
$\frac{F_{e}}{F_{g}} = \frac{1}{4 π ϵ} \frac{q_{e}^{2}}{r^{2}} \times \frac{r^{2}}{G m_{e} M_{p}} == 2.27 \times 10^{39}$

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Similar questions

What is the ratio of electrostatic force and gravitational force between a proton and electron at 1mm distance?

Mass of proton – $1.67 \times 10^{- 27}$ kg

Mass of electron – $9.11 \times 10^{- 31}$ kg

Charge of electron – $1.6 \times 10^{- 19}$ kg

What is the ratio of electrostatic force and gravitational force between a proton and electron at 1 mm distance?

Mass of proton – $1.67 \times 10^{- 27} k g$

Mass of electron – $9.11 \times 10^{- 31} k g$

Charge of electron – $1.6 \times 10^{- 19} C$

9.1 \times 10^{31} k g

1.7 \times 10^{- 27} k g

1 ˚ A (= 10^{- 10} m)

(m_{p} = 1.67 \times 10^{- 27} k g, m_{e} = 9.11 \times 10^{- 31} k g)

m_{p} = 1.67 \times 10^{- 27} k g

m_{e} = 9.1 \times 10^{- 31} k g

q_{p} = 1.6 \times 10^{- 19} C

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