The mass of an object $P$ is double the mass of $Q$ . If both move with the same velocity, then the ratio of K.E. of $P$ to $Q$ is

1 : 2

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2 : 1

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1 : 4

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4 : 1

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Solution

The correct option is B 2 : 1
$M_{P} = 2 \times M_{Q}$
$V_{P} = V_{Q}$

$K . E_{P} : K . E_{Q} = ?$

$⟹ \frac{1}{2} M_{P} V_{P}^{2} : \frac{1}{2} M_{Q} V_{Q}^{2}$
Since $V_{P}$ = $V_{Q}$
$⟹ M_{P} : M_{Q}$
$⟹ 2 \times M_{Q} : M_{Q}$
$⟹ 2 : 1$

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The mass of an object P is double the mass of Q. If both move with the same velocity, then the ratio of K.E. of P to Q is

The correct option is B 2 : 1MP=2×MQVP=VQK.EP:K.EQ=?⟹12MPV2P:12MQV2QSince VP =VQ⟹MP:MQ⟹2×MQ:MQ⟹2:1

The mass of an object $P$ is double the mass of $Q$ . If both move with the same velocity, then the ratio of K.E. of $P$ to $Q$ is

The correct option is B 2 : 1
$M_{P} = 2 \times M_{Q}$
$V_{P} = V_{Q}$

$K . E_{P} : K . E_{Q} = ?$

$⟹ \frac{1}{2} M_{P} V_{P}^{2} : \frac{1}{2} M_{Q} V_{Q}^{2}$
Since $V_{P}$ = $V_{Q}$
$⟹ M_{P} : M_{Q}$
$⟹ 2 \times M_{Q} : M_{Q}$
$⟹ 2 : 1$