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Faraday's Second Law

The mass of b...

Question

The mass of benzene in g that would be required to produce a current of one ampere (Assume current efficiency 50%) for three hour from the following data:
$C_{6} H_{6} + \frac{15}{2} O_{2} \to 6 C O_{2} + 2 H_{2} O$

0.58

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0.38

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0.24

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0.29

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Solution

The correct option is C 0.29
The balanced chemical reaction involves 15 electrons.
The number of faradays formed is $\frac{0.5 \times 1 \times 3 \times 3600}{96500} = 0.05595$
The mass of benzene required $\frac{0.05595}{15} \times 78 = 0.29$ g.

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