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Depression in Freezing Point

The mass of b...

Question

The mass of benzene which can freeze out on addition of 7.3 g of triphenyl methane to 1000 g of benzene at a temperature of ${0.2}^{\circ} C$ less than the normal freezing point of benzene is
$(K_{f} (C_{6} H_{6}) = 5.12 K k g m o l^{- 1})$

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Solution

$Δ T_{f} = K_{f} m \Rightarrow 0.2 = 5.12 \frac{7.3 \times 1000}{244 \times w} (M_{t r i p h e n y l m e t h a n e} = 244)$

w = mass of benzene = 766

Mass of benzene freezed out= 1000-766
= 234 g

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