The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

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The mass of chlorine (17Cl35) atom is 34.98 amu, mass of proton = 1.007825 amu, mass of neutron= 1.008665 amu. Then binding energy is :

The correct option is A 287.83 MevΔm=(17×1.007825)+(18×1.008665)−34.98 =0.308995amu =0.308995×931.478MeVc2.......[using 1amu=931.478MeVc2] =287.82MeVc2E=Δmc2 =287.82MeV

The mass of chlorine ( $_{17} C l^{35}$ ) atom is 34.98 amu, mass of proton = 1.007825 amu, mass of neutron= 1.008665 amu. Then binding energy is :

The correct option is A $287.83$ Mev
$Δ m = (17 \times 1.007825) + (18 \times 1.008665) - 34.98$
$= 0.308995 a m u$
$= 0.308995 \times 931.478 \frac{M e V}{c^{2}} . . . . . . . [$ using $1 a m u = 931.478 \frac{M e V}{c^{2}}]$
$= 287.82 \frac{M e V}{c^{2}}$
$E = Δ m c^{2}$
$= 287.82 M e V$