Question

The mass of $C{O}_2$ obtained when 60 g of calcium carbonate is treated with excess of hydrochloric acid is :

• A. 30.0 g
• B. 15.0 g
• C. 13.2 g
• D. 26.4 g

Answer 1

The correct option is D 26.4 g

$CaC{O}_3+2HCl\to CaC{l}_2+H_{2}O+C{O}_2$

According to the above equation 100 grams of $CaC{O}_3$ produces 44 grams of $C{O}_2$

So 60 grams of $CaC{O}_3$ produces X grams of $C{O}_2$

$100\times X=44\times 60$

$X=\frac{44\times 60}{100}=26.4g$

Hence option D is correct.