The mass of $C O_{2}$ produced from $620$ g mixture of $C_{2} H_{4} O_{2}$ & $O_{2}$ is (combustion reaction is exothermic) :

413.33 g

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593.04 g

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440 g

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320 g

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Solution

The correct option is C 440 g
The molar masses of $C_{2} H_{4} O_{2}, O_{2}$ and $C O_{2}$ are $60$ g/mole, $32$ g/mole and $44$ g/mole respectively.
$1$ mole of $C_{2} H_{4} O_{2}$ will react with $2$ moles of $O_{2}$ to produce $244$ moles of $C O_{2}$ .
Thus, $60 + 2 (32) = 124$ g of a mixture of $C_{2} H_{4} O_{2}$ and $O_{2}$ will produce $2 \times 44 = 88 g$ of $C O_{2}$ .
The mass of $C O_{2}$ produced on combustion of $620$ g mixture will be $\frac{88}{124} \times 620 = 440 g$ .

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