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Question

# The mass of 6.02×1023 molecules of a gas is 64.0 grams. What volume does 8.00 grams of the gas occupy at standard temperature and pressure?

A
2.80 L
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B
8.00 L
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C
11.2 L
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D
22.4 L
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E
64.0 L
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Solution

## The correct option is D 2.80 L6.02×1023 is Avogadro's number of molecules. It corresponds to 1 mole of gas. The mass of 1 mole of gas is 64.0 grams.8.00 grams of gas corresponds to 8.00g64.0g/mol=18.0moles At standard temperature and pressure, 1 mole of a gas occupies a volume of 22.4 L.So 18.0moles of a gas will occupy a volume of 22.4L/mol×18.0moles=2.80L

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