Question

The mass of Fe converted to its oxide $F{e}_3{O}_4$ by the action of 18 g of steam is:

• A. 42 g
• B. 42 mg
• C. 24 g
• D. 24 mg

Answer 1

The correct option is A

42 g

$3Fe+4H_{2}O\to F{e}_3{O}_4+4H_2$
$3\times 56$ g of Fe requires $4\times 18$ g of $H_{2}O$
Mass of Fe requires for 18 g of $H_{2}O$ is = $\frac{(3\times 56\times 18)}{(4\times 18)}=42g$