The mass of Fe converted to its oxide $F e_{3} O_{4}$ by the action of 18 g of steam is:

42 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

42 mg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 mg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 42 g
$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$
$3 \times 56$ g of Fe requires $4 \times 18$ g of $H_{2} O$
Mass of Fe requires for 18 g of $H_{2} O$ is = $\frac{(3 \times 56 \times 18)}{(4 \times 18)} = 42 g$

Suggest Corrections

Similar questions

The mass of Fe converted to its oxide $F e_{3} O_{4}$ by the action of 18 g of steam is:

3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

F e = 56 g

(F e_{3} O_{4})

8 g

F e = 56

F e + H_{2} O \to F e_{3} O_{4} + 4 H_{2}

Join BYJU'S Learning Program