Question

The mass of gas adsorbed, $x$, per unit mass of adsorbate, m, was measured at various pressures, $p$. A graph between $\log [\mathrm{x}/\mathrm{m}]$and $\log p$ gives a straight line with slope equal to $2$and the intercept equal to $0.4771$. The value of$[\mathrm{x}/\mathrm{m}]$at a pressure of $4$atm is:$\text{(Given}\log 3=0.4771\text{)}$

Answer 1

Step 1 : Given data

$c=\log k$, $x=2,k=3$

$$\begin{gathered} c=\log 3 \\ =0.4771 \end{gathered}$$

Step 2: Apply absorbed equation

$\frac{x}{m}=k{p}^x.....\left(1\right)$

Take logarithm on both sides

$\log \frac{x}{m}=\log k+x\log p$

Substitute the given values in the pressure equation

$\frac{x}{m}=3\times (4{)}^2$

$\frac{x}{m}=$48

Therefore the value for $\frac{x}{m}=48$