Question

The mass of $M{g}_3{N}_2$ produced, if $48g$ of $Mg$ metal is reacted with $34gm$ $N{H}_3$ gas is
$Mg+N{H}_3\to M{g}_3{N}_2+H_2$.

• A. $\frac{200}{3}gm$
• B. $\frac{100}{3}gm$
• C. $\frac{400}{3}gm$
• D. $\frac{150}{3}gm$

Answer 1

The correct option is A $\frac{200}{3}gm$

The balanced chemical equation is $3Mg+2N{H}_3\to M{g}_3{N}_2+3H_2$.
$48$ g of magnesium will react with $\frac{48\times 2\times 17}{24\times 3}=22.67$ g of ammonia.
However, $34$ g of ammonia is present.
Thus, magnesium is the limiting reagent.
The mass of magnesium nitride formed is $\frac{48\times 1\times 100}{24\times 3}=\frac{200}{3}$ g.